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प्रश्न
विकल्प
−2
2
0
4
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उत्तर
2
\[\int_{- 1}^1 \left| 1 - x \right| d x\]
\[ = \int_{- 1}^0 \left( 1 - x \right) dx + \int_0^1 \left( 1 - x \right) dx\]
\[ = \left[ x - \frac{x^2}{2} \right]_{- 1}^0 + \left[ x - \frac{x^2}{2} \right]_0^1 \]
\[ = 0 + 1 + \frac{1}{2} + 1 - \frac{1}{2} - 0\]
\[ = 2\]
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