Topics
Similarity
- Ratios of Areas of Two Triangles
- Basic Proportionality Theorem
- Property of an Angle Bisector of a Triangle
- Property of Three Parallel Lines and Their Transversals
- Similarity of Triangles (Corresponding Sides & Angles)
- Theorem of Areas of Similar Triangles
- Overview of Similarity
Pythagoras Theorem
- Pythagorean Triplet
- Property of 30°- 60°- 90° Triangle Theorem
- Property of 45°- 45°- 90° Triangle Theorem
- Theorem of Similarity in Right Angled Triangle
- Theorem of Geometric Mean
- Pythagoras Theorem
- Application of Pythagoras Theorem
- Apollonius Theorem
- Overview of Pythagoras Theorem
Circle
- Properties of Chords of a Circle
- Circles Passing Through One, Two, Three Points
- Secant and Tangent
- Tangent Theorem
- Tangent Segment Theorem
- Touching Circles
- Arc of the Circle
- Central Angle and the Measure of an Arc
- Congruence of Arcs
- Property of Sum of Measures of Arcs
- Inscribed Angle & Intercepted Arc
- Cyclic Quadrilateral
- Overview of Circle
- Theorem of Angle between Tangent and Secant
- Theorem of Internal Division of Chords
- Theorem of External Division of Chords
- Tangent Secant Segments Theorem
Geometric Constructions
- Construction of Similar Triangle
- Construction of a Tangent to a Circle at a Point on the Circle
- Construction of a Tangent to a Circle from a Point Outside the Circle
- Overview of Geometric Constructions
Co-ordinate Geometry
Trigonometry
Mensuration
Maharashtra State Board: Class 10
Formula: Cube
Cube (side = a)
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Lateral surface area = 4a2
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Total surface area = 6a2
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Volume = a3
Maharashtra State Board: Class 10
Formula: Cylinder
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Curved surface area = 2πrh
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Total surface area = 2πr(r + h)
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Volume = πr2h
Maharashtra State Board: Class 10
Formula: Cone
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Slant height l =\[\sqrt{h^2+r^2}\]
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Curved surface area = πrl
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Total surface area = πr(r + l)
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Volume = \[\frac{1}{3}\] × πr2h
Maharashtra State Board: Class 10
Formula: Sphere
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Surface area = 4πr2
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Volume = \[\frac{4}{3}\]πr3
Maharashtra State Board: Class 10
Formula: Hemisphere
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Curved surface area = 2πr2
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Total surface area of a solid hemisphere = 3πr2
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Volume = \[\frac{2}{3}\]πr3
Maharashtra State Board: Class 10
Formula: Frustum of Cone
Let radii r1 > r2, height h, slant height l
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Slant height: l = \[\sqrt{h^2+(r_1-r_2)^2}\]
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Curved surface area of a frustum: πl(r1 + r2)
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Total surface area of a frustum: πl(r1 + r2) + πr12 + πr22
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Volume: \[\frac{1}{3}\]πh(r12 + r22 + r1 × r2)
Maharashtra State Board: Class 10
Formula: Cuboid
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Lateral surface area = 2h(l + b)
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Total surface area = 2(lb + bh + hl)
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Volume = lbh
