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B Nirmala Shastry solutions for मॅथेमॅटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 13 - Theorems on Area [Latest edition]

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B Nirmala Shastry solutions for मॅथेमॅटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 13 - Theorems on Area - Shaalaa.com
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Solutions for Chapter 13: Theorems on Area

Below listed, you can find solutions for Chapter 13 of CISCE B Nirmala Shastry for मॅथेमॅटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई.


EXERCISE 13MULTIPLE CHOICE QUESTIONSMISCELLANEOUS EXERCISE
EXERCISE 13 [Pages 161 - 163]

B Nirmala Shastry solutions for मॅथेमॅटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई 13 Theorems on Area EXERCISE 13 [Pages 161 - 163]

EXERCISE 13 | Q 1. | Page 161

Find the area of parallelogram ABCD, if AD = 15 cm and P is a point on BC such that AP = 9 cm. Also find the area of parallelogram ABQR, where Q and R are points on CD produced.

EXERCISE 13 | Q 2. | Page 161

M is a point on side PQ of rectangle PQRS. SR is produced to a point N and MSRT is a parallelogram. PQ = 8.5 cm, PS = 6 cm. Find the area of

  1. parallelogram MSRT
  2. ΔMNT

EXERCISE 13 | Q 3. | Page 161

ABCD is a rectangle, AB = 15 cm, AC = 17 cm. Find the area of parallelogram PQCA.

EXERCISE 13 | Q 4. | Page 161

ABCD is a square of side 10 cm. Find the area of parallelogram BDPQ.

EXERCISE 13 | Q 5. | Page 161

The perimeter of parallelogram ABCD is 42 cm. If AP = 3 cm and AQ = 4 cm, calculate the sides of parallelogram ABCD.

EXERCISE 13 | Q 6. | Page 161

P is any point on the side AB of parallelogram ABCD. Prove that area (ΔAPD) + area (ΔPBC) = `1/2` area (|| gm ABCD).

EXERCISE 13 | Q 7. | Page 162

PQRS is a parallelogram. A is any point on SR. PA is produced to meet QR produced at B. Prove that area (ΔQAR) = area (ΔSAB).

EXERCISE 13 | Q 8. | Page 162

ABCD and PBCQ are parallelograms. Area of ΔPBC = 8 cm2. Calculate the area of parallelograms ABCD, PBCQ and ΔPCQ.

EXERCISE 13 | Q 9. | Page 162

In the given figure, AC || BH and AD || EF. Show area (ΔAHF) = area (pentagon ABCDE). [Hint: Join BC and DE.]


[Hint: Join BC and DE.]

EXERCISE 13 | Q 10. | Page 162

ABCD is a rectangle, AB = 4 cm, BC = 10 cm. Find the area of ΔRDC and || gm PQCD.

EXERCISE 13 | Q 11. | Page 162

ABCD and ABPQ are two parallelograms. Side AQ and BC are produced to meet at R. Show that area (ΔBCD) = area (ΔBPR).

EXERCISE 13 | Q 12. | Page 162

In the given figure, TQ || SR and PQ || TS. Prove that area (ΔPTS) = area (ΔTRQ).


[Hint: Join QS.]

EXERCISE 13 | Q 13. | Page 162

ABCD and APDR are parallelograms. P is the mid-point of BC and Q is on CD such that DQ : QC = 2 : 1. Area (ΔPQC) = 20 cm2. Find the areas of 

  1. ΔPDC
  2. ΔABP
  3. || gm APDR

EXERCISE 13 | Q 14. | Page 162

ABCD and BEFG are parallelograms and CE || AG. Prove that Area (|| gm ABCD) = Area (|| gm BEFG) 


[Hint: Prove Area (ΔABC) = Area (ΔGBE)]

EXERCISE 13 | Q 15. | Page 162

ABCD is a parallelogram, BC is produced to Q so that ∠DQC = 90°. AP ⊥ DC. If AP = 2.5 cm, BC = 4 cm and DQ = 5 cm, find the length of AB.


[Hint: Area of || gm = CD × AP = AD × DQ]

EXERCISE 13 | Q 16. | Page 163

ABCD is a parallelogram and AF || DE. Prove that area (|| gm DEFH) = area (|| gm ABCD).


[Hint: Each || gm is equal in area to || gm ADEG]

EXERCISE 13 | Q 17. | Page 163

In ΔABC, M is the mid-point of BC, L is a point on AB such that AL = 2LB. Find the area of ΔALM if area of ΔABC = 72 cm2.

EXERCISE 13 | Q 18. | Page 163

ABCD is a parallelogram, prove that 

  1. Area (ΔABC) = Area (ΔPAD)
  2. Area (ΔPAB) = Area (quadrilateral ACPD)

EXERCISE 13 | Q 19. | Page 163

D is the mid-point of AC. E is on BC such that BE = `1/3` BC. Area of ΔABC = 48 cm2. Find the area of ΔADB and ΔBDE.

EXERCISE 13 | Q 20. | Page 163

Area of ΔPCD = 10 cm2. Find the area of ΔADQ and parallelogram ABCD.

MULTIPLE CHOICE QUESTIONS [Pages 163 - 165]

B Nirmala Shastry solutions for मॅथेमॅटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई 13 Theorems on Area MULTIPLE CHOICE QUESTIONS [Pages 163 - 165]

MULTIPLE CHOICE QUESTIONS | Q 1. | Page 163

P is a point on side AB of parallelogram ABCD. Which of the following is true?

  1. Area of ΔAPD = `1/4` area || gm ABCD
  2. Area of ΔPDC = `1/2` area || gm ABCD
  3. Area of ΔAPD + area of ΔPBC = `1/2` parallelogram ABCD
  • only A

  • only B

  • A and B

  • B and C

MULTIPLE CHOICE QUESTIONS | Q 2. | Page 163

In || gm ABCD, M is a point on AB, ∠DMC = 90°. DM = 15 cm, DC = 17 cm. ∴  Area of || gm ABCD is:

  • 60 cm2

  • 68 cm2

  • 120 cm

  • 136 cm2

MULTIPLE CHOICE QUESTIONS | Q 3. (i) | Page 163

PQRS is a rectangle and AQRB is a || gm, SR = 9 cm, PS = 12 cm


Area of ΔCQR =

  • 108 cm2

  • 72 cm2

  • 54 cm2

  • 42 cm2

MULTIPLE CHOICE QUESTIONS | Q 3. (ii) | Page 163

PQRS is a rectangle and AQRB is a || gm, SR = 9 cm, PS = 12 cm


Area of || gm AQRB =

  • 2 area of ΔBSR

  • 2 area of ΔPAQ

  • 108 cm2

  • 144 cm2

MULTIPLE CHOICE QUESTIONS | Q 4. | Page 164

Area of ΔPMQ = 72 cm2, Area of || gm LMNO =

  • `1/2` area LMNQ

  • 108 cm2

  • 144 cm2

  • 72 cm2

MULTIPLE CHOICE QUESTIONS | Q 5. | Page 164

ABCD is a rectangle. PACQ is a || gm. AB = 12 cm, AC = 15 cm. Area of || gm PACQ =

  • 180 cm2

  • 108 cm2

  • 54 cm2

  • 90 cm2

MULTIPLE CHOICE QUESTIONS | Q 6. | Page 164

Area of || gm ABCD =

  • AP × PC

  • AD × RC

  • AD × AP

  • AB × AP

MULTIPLE CHOICE QUESTIONS | Q 7. | Page 164

AM is the median of ΔABC. Area of ΔABC = 140 cm2. AN : NC = 3 : 2. Area of ΔMNC =

  • 70 cm2

  • 35 cm2

  • 28 cm2

  • 42 cm2

MULTIPLE CHOICE QUESTIONS | Q 8. | Page 164

P and Q are mid points of AB and AC of ΔABC. Which of the following is not true?

  • Area of ΔBQC = Area of ΔBPC

  • Area of ΔPBQ = Area of ΔPCQ

  • Area of ΔAPQ = Area of ΔBOC

  • Area of ΔABQ = Area of ΔBQC

MULTIPLE CHOICE QUESTIONS | Q 9. | Page 164

In ΔABC, P, M and N are mid points of sides AB, BC and AC. If area of ΔABC = 120 cm2, Area of || gm APMN =

  • 60 cm2

  • 72 cm2

  • 75 cm2

  • 80 cm2

MULTIPLE CHOICE QUESTIONS | Q 10. | Page 164

ABCD is a rectangle, DBCE is a || gm. Area of || gm DBCE =

  • 320 cm2

  • 192 cm2

  • 160 cm2

  • 240 cm2

Direction for Questions 11 to 14: In each of the following questions, a statement of assertion (A) is given and a statement of Reason (R) given below it choose the correct option for each question.

MULTIPLE CHOICE QUESTIONS | Q 11. | Page 164

Assertion: If area of ΔAOD = 18 cm2 then area of parallelogram ABCD = 72 cm2.

Reason: The diagonals of a parallelogram bisect each other.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A.

  • A is true but R is false.

  • A is false but R is true.

MULTIPLE CHOICE QUESTIONS | Q 12. | Page 164

Assertion: Area of ΔPDC = 160 cm2 and area of parallelogram ABCD = 320 m2.


Reason: Area of a right angled Δ = `1/2` product of sides containing right angle.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A.

  • A is true but R is false.

  • A is false but R is true.

MULTIPLE CHOICE QUESTIONS | Q 13. | Page 165

Assertion: A median of a triangle divides it into 2 triangles of equal area.

Reason: The two triangles so formed are congruent.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A.

  • A is true but R is false.

  • A is false but R is true.

MULTIPLE CHOICE QUESTIONS | Q 14. | Page 165

Assertion: AB || DC in the figure. Area of ΔAOD = Area of ΔBOC.


Reason: Two Δs on the same base and between the same parallel lines have equal area.

  • Both A and R are true and R is the correct reason for A.

  • Both A and R are true but R is the incorrect reason for A.

  • A is true but R is false.

  • A is false but R is true.

MISCELLANEOUS EXERCISE [Pages 165 - 166]

B Nirmala Shastry solutions for मॅथेमॅटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई 13 Theorems on Area MISCELLANEOUS EXERCISE [Pages 165 - 166]

MISCELLANEOUS EXERCISE | Q 1. | Page 165

ABCD is a trapezium in which AD || BC. M is the mid-point of CD. Through M, PQ is drawn || to AB with P on AD produced and Q on BC.

  1. Show that ΔDPM ≅ ΔCQM
  2. Prove that area of ΔABM = `1/2` × area of trapezium ABCD.

MISCELLANEOUS EXERCISE | Q 2. | Page 165

The area of ΔABC = 18 cm2. Find the distance between the || lines AD and BC if BC = 8 cm. Calculate the area of || gm BCDE.

MISCELLANEOUS EXERCISE | Q 3. | Page 165

ABCD is a rectangle and BCED is a parallelogram. If BC = 12 cm and CE = 15 cm, find the area of

  1. Parallelogram BCED
  2. ΔCDE

MISCELLANEOUS EXERCISE | Q 4. | Page 165

In ΔPQR, PM and QN are medians. Area of ΔGQM = 15 cm2. Find the area of ΔPQR.

MISCELLANEOUS EXERCISE | Q 5. | Page 165

ABCD is a trapezium with AB with AB || DC and diagonals AC and BD intersect at O. Prove that area of ΔAOD = area of ΔBOC.

MISCELLANEOUS EXERCISE | Q 6. | Page 165

Area of ΔABD = 30 cm2. Find the area of ΔADC, if BD = `5/8` BC.

MISCELLANEOUS EXERCISE | Q 7. | Page 165

AM is the median of ΔABC. N is on AC such that AN : NC = 3 : 2. If area of ΔMNC = 12 cm2, find the area of ΔABC.

MISCELLANEOUS EXERCISE | Q 8. | Page 165

In ΔABC, PQ || BC. Prove that

  1. Area (ΔPBC) = Area (ΔQBC)
  2. Area (ΔPOB) = Area (ΔQOC)
MISCELLANEOUS EXERCISE | Q 9. | Page 166

In adjoining figure, ABCD is a parallelogram, AQ = QB. CB and DQ are produced to meet at P. Prove that

  1. Area (ΔAQD) = Area (ΔAQP)
  2. Area (ΔDCP) = Area (|| gm ABCD)
MISCELLANEOUS EXERCISE | Q 10. | Page 166

In the given figure, PQRS and PXYZ are parallelograms. Prove that they are of equal area.


[Hint: Join XQ. Area (ΔXPQ) = `1/2` of each || gm]

MISCELLANEOUS EXERCISE | Q 11. | Page 166

In the given figure, PQRS and PXYZ are two parallelograms of equal area. Prove that SX || YR.

Solutions for 13: Theorems on Area

EXERCISE 13MULTIPLE CHOICE QUESTIONSMISCELLANEOUS EXERCISE
B Nirmala Shastry solutions for मॅथेमॅटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 13 - Theorems on Area - Shaalaa.com

B Nirmala Shastry solutions for मॅथेमॅटिक्स [इंग्रजी] इयत्ता ९ आयसीएसई chapter 13 - Theorems on Area

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