HSC Arts इयत्ता ११ - Tamil Nadu Board of Secondary Education Question Bank Solutions

A year is selected at random. What is the probability that it contains 53 Sundays

A year is selected at random. What is the probability that it is a leap year which contains 53 Sundays

Suppose the chances of hitting a target by a person X is 3 times in 4 shots, by Y is 4 times in 5 shots, and by Z is 2 times in 3 shots. They fire simultaneously exactly one time. What is the probability that the target is damaged by exactly 2 hits?

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A, B, and C try to hit a target simultaneously but independently. Their respective probabilities of hitting the target are `3/4, 1/2, 5/8`. The probability that the target is hit by A or B but not by C is

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If A and B are any two events, then the probability that exactly one of them occur is

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Let A and B be two events such that `"P"(bar ("A" ∪ "B")) = 1/6, "P"("A" ∩ "B") = 1/4` and `"P"(bar"A") = 1/4`. Then the events A and B are

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A letter is taken at random from the letters of the word ‘ASSISTANT’ and another letter is taken at random from the letters of the word ‘STATISTICS’. The probability that the selected letters are the same is

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If two events A and B are independent such that P(A) = 0.35 and P(A ∪ B) = 0.6, then P(B) is

For the curve y = x³ given in Figure 1.67, draw
y = −x³ 

For the curve y = x³ given in Figure 1.67, draw
y = x³ + 1 

For the curve y = x³ given in Figure 1.67, draw
y = x³ − 1 

For the curve y = x³ given in Figure 1.67, draw
y = (x + 1)³ with the same scale

For the curve y = `x^((1/3))` given in Figure 1.68, draw

y = `- x^((1/3))`

For the curve y = `x^((1/3))` given in Figure 1.68, draw

y = `x^((1/3)) + 1`

For the curve y = `x^((1/3))` given in Figure 1.68, draw

y = `x^((1/3)) - 1`

For the curve y = `x^((1/3))` given in Figure 1.68, draw

y = `(x + 1)^((1/3))`

Graph the functions f(x) = x³ and g(x) = `root(3)(x)` on the same coordinate plane. Find f o g and graph it on the plane as well. Explain your results

Write the steps to obtain the graph of the function y = 3(x − 1)² + 5 from the graph y = x² 

From the curve y = sin x, graph the function.
y = sin(− x)

From the curve y = sin x, graph the function
y = − sin(−x)