SSC (English Medium) इयत्ता १० वी - Maharashtra State Board Question Bank Solutions

Identify, with reason, if the following is a Pythagorean triplet.

(5, 12, 13)

Identify, with reason, if the following is a Pythagorean triplet.
(24, 70, 74)

Identify, with reason, if the following is a Pythagorean triplet.
(10, 24, 27)

Identify, with reason, if the following is a Pythagorean triplet.
(11, 60, 61)

For finding AB and BC with the help of information given in the figure, complete following activity.

AB = BC ..........

∴ ∠BAC =

∴ AB = BC = × AC

                 = × `sqrt8`

                 = × `2sqrt2`

                 =

In the given figure, ∠DFE = 90°, FG ⊥ ED, If GD = 8, FG = 12, find (1) EG (2) FD and (3) EF

In the given figure, M is the midpoint of QR. ∠PRQ = 90°. Prove that, PQ² = 4PM² – 3PR².

Walls of two buildings on either side of a street are parallel to each other. A ladder 5.8 m long is placed on the street such that its top just reaches the window of a building at the height of 4 m. On turning the ladder over to the other side of the street, its top touches the window of the other building at a height 4.2 m. Find the width of the street.

In ∆ABC, AB = 10, AC = 7, BC = 9, then find the length of the median drawn from point C to side AB.

In the given figure, point T is in the interior of rectangle PQRS, Prove that, TS² + TQ² = TP² + TR² (As shown in the figure, draw seg AB || side SR and A-T-B)

Some question and their alternative answer are given. Select the correct alternative.

If a, b, and c are sides of a triangle and a² + b² = c², name the type of triangle.

Find the length of the hypotenuse of a right angled triangle if remaining sides are 9 cm and 12 cm.

Pranali and Prasad started walking to the East and to the North respectively, from the same point and at the same speed. After 2 hours distance between them was \[15\sqrt{2}\]

In ∆ABC, ∠BAC = 90°, seg BL and seg CM are medians of ∆ABC. Then prove that:
4(BL² + CM²) = 5 BC²

Prove that:

`(sin^2θ)/(cosθ) + cosθ = secθ`

In ∆ABC, seg AD ⊥ seg BC, DB = 3CD.

Prove that: 2AB² = 2AC² + BC²