PUC Science 2nd PUC Class 12 - Karnataka Board PUC Question Bank Solutions

f(x)=| x+2 | on R .

f (x) = \[-\] | x + 1 | + 3 on R .

f(x) = 16x² \[-\] 16x + 28 on R ?

f(x) = x³ \[-\] 1 on R .

f(x) = (x \[-\] 5)⁴.

f(x) = x³ \[-\] 3x.

f(x) = x³  (x \[-\] 1)² .

f(x) =  (x \[-\] 1) (x+2)². 

f(x) = \[\frac{1}{x^2 + 2}\] .

f(x) =  x³ \[-\] 6x² + 9x + 15 . 

f(x) = sin 2x, 0 < x < \[\pi\] .

f(x) =  sin x \[-\] cos x, 0 < x < 2\[\pi\] .

f(x) =  cos x, 0 < x < \[\pi\] .

`f(x)=sin2x-x, -pi/2<=x<=pi/2`

`f(x)=2sinx-x, -pi/2<=x<=pi/2`

f(x) =\[x\sqrt{1 - x} , x > 0\].