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(English Medium) ICSE Class 9 - CISCE Question Bank Solutions

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At what rate of interest per annum will a sum of Rs. 62,500 earn a compound interest of Rs. 5,100 in one year? The interest is to be compounded half yearly.

[3] Compound Interest [Using Formula]
Chapter: [3] Compound Interest [Using Formula]
Concept: undefined >> undefined

In what time will Rs. 1,500 yield Rs. 496.50 as compound interest at 20% per year compounded half-yearly ?

[3] Compound Interest [Using Formula]
Chapter: [3] Compound Interest [Using Formula]
Concept: undefined >> undefined

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Calculate the C.I. on Rs. 3,500 at 6% per annum for 3 years, the interest being compounded half-yearly.

Do not use mathematical tables. Use the necessary information from the following:

(1.06)3 = 1.191016; (1.03)3 = 1.092727
(1.06)6 =1.418519; (1.03)6 = 1.194052

[3] Compound Interest [Using Formula]
Chapter: [3] Compound Interest [Using Formula]
Concept: undefined >> undefined

Find the difference between compound interest and simple interest on Rs.12,000 and in  `1 1/2` years at 10% compounded yearly.

[3] Compound Interest [Using Formula]
Chapter: [3] Compound Interest [Using Formula]
Concept: undefined >> undefined

Find the difference between compound interest and simple interest on Rs. 12,000 and in `1 1/2` years at 10% compounded half-yearly.

[3] Compound Interest [Using Formula]
Chapter: [3] Compound Interest [Using Formula]
Concept: undefined >> undefined

Simplify : ( x + 6 )( x + 4 )( x - 2 )

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Simplify : ( x - 6 )( x - 4 )( x + 2 )

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Simplify : ( x - 6 )( x - 4 )( x - 2 )

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Simplify: (x + 6) (x − 4) (x − 2)

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
( 2x + 3y )( 4x2 + 6xy + 9y2 )

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
`( 3x - 5/x )( 9x^2 + 15 + 25/x^2)`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
`(a/3 - 3b)(a^2/9 + ab + 9b^2)`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Find : (a + b)(a + b)

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Find : (a + b)(a + b)(a + b)

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Find : (a - b)(a - b)(a - b)

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Prove that :  x2+ y2 + z2 - xy - yz - zx  is always positive.

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If a + b = 11 and a2 + b2 = 65; find a3 + b3.

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If x = 3 + 2√2, find :
(i) `1/x`

(ii) `x - 1/x`

(iii) `( x - 1/x )^3`

(iv) `x^3 - 1/x^3`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If x + 5y = 10; find the value of x3 + 125y3 + 150xy − 1000.

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If a − 2b + 3c = 0; state the value of a3 − 8b3 + 27c3.

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined
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