Find: (A + B)(A + B) - Mathematics

Find : (a + b)(a + b)

बेरीज

(a + b)(a + b) = (a + b)²= a × a + a × b + b × a + b × b
= a² + ab + ab + b²= a² + b² + 2ab

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Special Product

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पाठ 4: Expansions (Including Substitution) - Exercise 4 (E) [पृष्ठ ६६]

पाठ 4 Expansions (Including Substitution)
Exercise 4 (E) | Q 11.1 | पृष्ठ ६६

Simplify : ( x - 6 )( x - 4 )( x - 2 )

Simplify: (x + 6) (x − 4) (x − 2)

Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
( 2x + 3y )( 4x² + 6xy + 9y²)

Simplify using following identity : `( a +- b )(a^2 +- ab + b^2) = a^3 +- b^3`
`(a/3 - 3b)(a^2/9 + ab + 9b^2)`

Find : (a + b)(a + b)(a + b)

Find : (a - b)(a - b)(a - b)

If a + b = 11 and a² + b² = 65; find a³ + b³.

If a − 2b + 3c = 0; state the value of a³− 8b³ + 27c³.

Using suitable identity, evaluate (104)³

Simplify :
`[(x^2 - y^2)^3 + (y^2 - z^2)^3 + (z^2 - x^2)^3]/[(x - y)^3 + (y - z)^3 + (z - x)^3]`