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(English Medium) ICSE Class 9 - CISCE Question Bank Solutions

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If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a"  - (1)/"a"`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a"  + (1)/"a"`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

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If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a"^2 - (1)/"a"^2`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If 2x + 3y = 10 and xy = 5; find the value of 4x2 + 9y2

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If x + y + z = 12 and xy + yz + zx = 27; find x2 + y2 + z2.

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If a2 + b2 + c2 = 41 and a + b + c = 9; find ab + bc + ca.

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If p2 + q2 + r2 = 82 and pq + qr + pr = 18; find p + q + r.

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If x + y + z = p and xy + yz + zx = q; find x2 + y2 + z2.

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If `"a"^2 + (1)/"a"^2 = 14`; find the value of `"a"  + (1)/"a"`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If `x^2 + (1)/x^2 = 18`; find : `x - (1)/x` 

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If `"p"  + (1)/"p" = 6`; find : `"p"^2 + (1)/"p"^2`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If `"p"  + (1)/"p" = 6`; find : `"p"^4 + (1)/"p"^4`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If `"r"  - (1)/"r" = 4`; find: `"r"^2 + (1)/"r"^2`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If `"r"  - (1)/"r" = 4`; find : `"r"^4 + (1)/"r"^4`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If `"a" + (1)/"a" = 2`, then show that `"a"^2 + (1)/"a"^2 = "a"^3 + (1)/"a"^3 = "a"^4 + (1)/"a"^4`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

If `x + (1)/x = "p", x - (1)/x = "q"`; find the relation between p and q.

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Simplify:
(4x + 5y)2 + (4x - 5y)2

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Simplify:
(7a +5b)2 - (7a - 5b)2

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Simplify:

`("a" - 1/"a")^2 + ("a" + 1/"a")^2`

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined

Simplify:
(x + y - z)2 + (x - y + z)2

[4] Expansions
Chapter: [4] Expansions
Concept: undefined >> undefined
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