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Find the third proportional to Rs. 3, Rs. 12
Concept: undefined >> undefined
Find the third proportional to `5(1)/(4) and 7.`
Concept: undefined >> undefined
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Find the mean proportion of: 5 and 80
Concept: undefined >> undefined
Find the mean proportion of: `(1)/(12) and (1)/(75)`
Concept: undefined >> undefined
Find the mean proportion of: 8.1 and 2.5
Concept: undefined >> undefined
Find the mean proportion of: (a – b) and (a³ – a²b), a> b
Concept: undefined >> undefined
If a, 12, 16 and b are in continued proportion find a and b.
Concept: undefined >> undefined
What number must be added to each of the numbers 5, 11, 19 and 37 so that they are in proportion?
Concept: undefined >> undefined
What number should be subtracted from each of the numbers 23, 30, 57 and 78 so that the remainders are in proportion ?
Concept: undefined >> undefined
If x + 5 is the mean proportion between x + 2 and x + 9, find the value of x.
Concept: undefined >> undefined
If 2x – 1, 5x – 6, 6x + 2 and 15x – 9 are in proportion, find the value of x.
Concept: undefined >> undefined
What number must be added to each of the numbers 16, 26 and 40 so that the resulting numbers may be in continued proportion?
Concept: undefined >> undefined
Find two numbers such that the mean proportional between them is 28 and the third proportional to them is 224.
Concept: undefined >> undefined
If b is the mean proportional between a and c, prove that a, c, a² + b², and b² + c² are proportional.
Concept: undefined >> undefined
If b is the mean proportional between a and c, prove that (ab + bc) is the mean proportional between (a² + b²) and (b² + c²).
Concept: undefined >> undefined
If y is mean proportional between x and z, prove that xyz (x + y + z)³ = (xy + yz + zx)³.
Concept: undefined >> undefined
If a + c = mb and `1/b + 1/d = m/c`, prove that a, b, c and d are in proportion.
Concept: undefined >> undefined
If `x/a = y/b = z/c`, prove that `x^3/a^2 + y^3/b^2 + z^3/c^2 = (x+ y+ z)^3/(a + b+ c)^2`
Concept: undefined >> undefined
If `x/a = y/b = z/c`, prove that `[(a^2x^2 + b^2y^2 + c^2z^2)/(a^2x + b^3y +c^3z)]^3 = "xyz"/"abc"`
Concept: undefined >> undefined
If `x/a = y/b = z/c`, prove that `"ax - by"/((a + b)(x- y)) + "by - cz"/((b + c)(y - z)) + "cz - ax"/((c + a)(z - x)` = 3
Concept: undefined >> undefined
