Advertisements
Advertisements
प्रश्न
If a, 12, 16 and b are in continued proportion find a and b.
Advertisements
उत्तर
∵ a, 12, 16, b are in continued proportion, then
`a/(12) = (12)/(16) = (16)/b`
⇒ `a/(12) = (12)/(16)`
⇒ 16a = 144
⇒ a = `(144)/(16)` = 9
and `(12)/(16) = (16)/b`
⇒ 12b = 16 x 16 = 256
b = `(256)/(12) = (64)/(3) = 21(1)/(3)`
Hence a = 9, b = `(64)/(3) or 21(1)/(3)`.
APPEARS IN
संबंधित प्रश्न
If y is the mean proportional between x and z; show that xy + yz is the mean proportional between x2 + y2 and y2 + z2.
if `a/b = c/d` prove that each of the given ratio is equal to: `((8a^3 + 15c^3)/(8b^3 + 15d^3))^(1/3)`
Find the mean proportion of the following :
ab3 and a3b
If a : b = c : d, show that (a - c) b2 : (b - d) cd = (a2 - b2 - ab) : (c2 - d2 - cd).
Find the third proportional to Rs. 3, Rs. 12
Find the mean proportion of: 8.1 and 2.5
Determine if the following numbers are in proportion:
33, 121, 9, 96
If a, b, c and d are in proportion, prove that: (5a + 7b) (2c – 3d) = (5c + 7d) (2a – 3b).
A student said that the ratios `3/4` and `9/16` were proportional. What error did the student make?
What number must be added to each of the numbers 4, 6, 8, 11 in order to get the four numbers in proportion?
