Advertisements
Advertisements
प्रश्न
Find the mean proportion of the following :
ab3 and a3b
Advertisements
उत्तर
Let x be the mean proportion
ab3 : x : : x : a3b
⇒ x × x = ab3 x a3b
⇒ x2 = a4b4
⇒ x = `sqrt ("a"^4"b"^4)`
⇒ x = a2b2
The mean proportion is a2b2
APPEARS IN
संबंधित प्रश्न
If x, y, z are in continued proportion, prove that `(x + y)^2/(y + z)^2 = x/z`
If x + 5 is the mean proportional between x + 2 and x + 9; find the value of x.
Find the third proportional to `x/y + y/x` and `sqrt(x^2 + y^2)`
Using properties of proportion, solve for x:
`(3x + sqrt(9x^2 - 5))/(3x - sqrt(9x^2 - 5)) = 5`
Find the fourth proportional to 2xy, x2 and y2.
The following numbers, K + 3, K + 2, 3K – 7 and 2K – 3 are in proportion. Find k.
A car travels 90 km in 3 hours with constant speed. It will travel 140 km in 5 hours at the same speed
Write the mean and extreme terms in the following ratios and check whether they are in proportion.
400 gm is to 50 gm and 25 rupees is to 625 rupees
Find the missing number in the box in the proportion:
`16/36 = square/63 = 36/square = square/117`
The mean proportional between 4 and 9 is ______.
