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In Fig. below, M, N and P are the mid-points of AB, AC and BC respectively. If MN = 3 cm, NP = 3.5 cm and MP = 2.5 cm, calculate BC, AB and AC.

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

ABC is a triangle and through A, B, C lines are drawn parallel to BC, CA and AB respectively
intersecting at P, Q and R. Prove that the perimeter of ΔPQR is double the perimeter of
ΔABC

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

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In Fig. below, BE ⊥ AC. AD is any line from A to BC intersecting BE in H. P, Q and R are
respectively the mid-points of AH, AB and BC. Prove that ∠PQR = 90°.

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

ABCD is a kite having AB = AD and BC = CD. Prove that the figure formed by joining the
mid-points of the sides, in order, is a rectangle.

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

Let Abc Be an Isosceles Triangle in Which Ab = Ac. If D, E, F Be the Mid-points of the Sides Bc, Ca and a B Respectively, Show that the Segment Ad and Ef Bisect Each Other at Right Angles.

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

ABC is a triang D is a point on AB such that AD = `1/4` AB and E is a point on AC such that AE = `1/4` AC. Prove that DE = `1/4` BC.

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

In below Fig, ABCD is a parallelogram in which P is the mid-point of DC and Q is a point on AC such that CQ = `1/4` AC. If PQ produced meets BC at R, prove that R is a mid-point of BC.

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

Give a method to find the centre of a given circle.

[9] Circles
Chapter: [9] Circles
Concept: undefined >> undefined

In the below Fig, ABCD and PQRC are rectangles and Q is the mid-point of Prove thaT

i) DP = PC (ii) PR = `1/2` AC

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

ABCD is a parallelogram, E and F are the mid-points of AB and CD respectively. GH is any line intersecting AD, EF and BC at G, P and H respectively. Prove that GP = PH.

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

BM and CN are perpendiculars to a line passing through the vertex A of a triangle ABC. If
L is the mid-point of BC, prove that LM = LN.

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

Show that the line segments joining the mid-points of the opposite sides of a quadrilateral
bisect each other.

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

Fill in the blank to make the following statement correct

The triangle formed by joining the mid-points of the sides of an isosceles triangle is         

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

Fill in the blank to make the following statement correct:

The triangle formed by joining the mid-points of the sides of a right triangle is            

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

Fill in the blank to make the following statement correct:

The figure formed by joining the mid-points of consecutive sides of a quadrilateral is           

[8] Quadrilaterals
Chapter: [8] Quadrilaterals
Concept: undefined >> undefined

In a ΔABC, P and Q are respectively the mid-points of AB and BC and R is the mid-point
of AP. Prove that :

(1) ar (Δ PBQ) = ar (Δ ARC)

(2) ar (Δ PRQ) =`1/2`ar (Δ ARC)

(3) ar (Δ RQC) =`3/8` ar (Δ ABC) .

[4.05] Area
Chapter: [4.05] Area
Concept: undefined >> undefined

A circular park of radius 40 m is situated in a colony. Three boys Ankur, Amit and Anand are sitting at equal distance on its boundary each having a toy telephone in his hands to talk
to each other.

[9] Circles
Chapter: [9] Circles
Concept: undefined >> undefined

In Fig. below, ABC and BDE are two equilateral triangles such that D is the mid-point of
BC. AE intersects BC in F. Prove that

(1)  ar (Δ BDE) = `1/2` ar (ΔABC) 

(2) Area ( ΔBDE) `= 1/2 ` ar (ΔBAE)

(3)  ar (BEF) = ar (ΔAFD)

(4) area (Δ ABC) = 2 area (ΔBEC)

(5) ar (ΔFED) `= 1/8` ar (ΔAFC) 

(6) ar (Δ BFE) = 2 ar (ΔEFD)

[4.05] Area
Chapter: [4.05] Area
Concept: undefined >> undefined

In the below fig. D and E are two points on BC such that BD = DE = EC. Show that ar
(ΔABD) = ar (ΔADE) = ar (ΔAEC).

[4.05] Area
Chapter: [4.05] Area
Concept: undefined >> undefined

In a ΔABC, if L and M are points on AB and AC respectively such that LM || BC. Prove
that:

(1) ar (ΔLCM ) = ar (ΔLBM )
(2) ar (ΔLBC) = ar (ΔMBC)
(3) ar (ΔABM) ar (ΔACL)
(4) ar (ΔLOB) ar (ΔMOC)

[4.05] Area
Chapter: [4.05] Area
Concept: undefined >> undefined
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