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Science (English Medium) इयत्ता १२ - CBSE Question Bank Solutions for Mathematics

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Mathematics
< prev  2601 to 2620 of 8190  next > 

Find the inverse of the matrices (if it exists).

`[(1,0,0),(3,3,0),(5,2,-1)]`

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Find the inverse of the matrices (if it exists).

`[(2,1,3),(4,-1,0),(-7,2,1)]`

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

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Find the inverse of the matrices (if it exists).

`[(1,-1,2),(0,2,-3),(3,-2,4)]`

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Find the inverse of the matrices (if it exists).

`[(1,0,0),(0, cos alpha, sin alpha),(0, sin alpha, -cos alpha)]`

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Let A = `[(3,7),(2,5)]` and B = `[(6,8),(7,9)]`. Verify that (AB)−1 = B−1A−1.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

If A = `[(3,1),(-1,2)]` show that A2 – 5A + 7I = 0. Hence, find A–1.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

For the matrix A = `[(3,2),(1,1)]` find the numbers a and b such that A2 + aA + bI = 0.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

For the matrix A = `[(1,1,1),(1,2,-3),(2,-1,3)]` show that A3 − 6A2 + 5A + 11 I = 0. Hence, find A−1.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

If A = `[(2,-1,1),(-1,2,-1),(1,-1,2)]` verify that A3 − 6A2 + 9A − 4I = 0 and hence find A−1.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

If A is an invertible matrix of order 2, then det (A−1) is equal to ______.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

If A−1 = `[(3,-1,1),(-15,6,-5),(5,-2,2)]` and B = `[(1,2,-2),(-1,3,0),(0,-2,1)]`, find (AB)−1.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Let A = `[(1,2,1),(2,3,1),(1,1,5)]` verify that

  1. [adj A]–1 = adj(A–1)
  2. (A–1)–1 = A
[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

If x, y, z are nonzero real numbers, then the inverse of matrix A = `[(x,0,0),(0,y,0),(0,0,z)]` is ______.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Let A = `[(1, sin theta, 1),(-sin theta,1,sin theta),(-1, -sin theta, 1)]` where 0 ≤ θ ≤ 2π, then ______.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Show that the three lines with direction cosines `12/13, (-3)/13, (-4)/13;  4/13, 12/13, 3/13;  3/13, (-4)/13, 12/13 ` are mutually perpendicular.

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Show that the line through the points (1, −1, 2) (3, 4, −2) is perpendicular to the line through the points (0, 3, 2) and (3, 5, 6).

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Show that the line through the points (4, 7, 8) (2, 3, 4) is parallel to the line through the points (−1, −2, 1), (1, 2, 5).

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector `3hati+2hatj-2hatk`.

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the equation of the line in vector and in Cartesian form that passes through the point with position vector `2hati -hatj+4hatk`  and is in the direction `hati + 2hatj - hatk`.

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the Cartesian equation of the line which passes through the point (−2, 4, −5) and parallel to the line given by `(x+3)/3 = (y-4)/5 = (z+8)/6`.

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined
< prev  2601 to 2620 of 8190  next > 
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