English Medium इयत्ता १० - CBSE Question Bank Solutions

Proved that `(1 + secA)/secA = (sin^2A)/(1 - cos A)`.

If tan θ = `x/y`, then cos θ is equal to ______.

sec θ when expressed in term of cot θ, is equal to ______.

Read the following passage:

Two schools 'P' and 'Q' decided to award prizes to their students for two games of Hockey ₹ x per student and Cricket ₹ y per student. School 'P' decided to award a total of ₹ 9,500 for the two games to 5 and 4 Students respectively; while school 'Q' decided to award ₹ 7,370 for the two games to 4 and 3 students respectively.

Based on the above information, answer the following questions:

1. Represent the following information algebraically (in terms of x and y).
2. (a) What is the prize amount for hockey?
   OR
   (b) Prize amount on which game is more and by how much?
3. What will be the total prize amount if there are 2 students each from two games?

Which of the following is true for all values of θ (0° ≤ θ ≤ 90°)?

(sec² θ – 1) (cosec² θ – 1) is equal to ______.

(1 – cos² A) is equal to ______.

Prove that `(1 + tan^2 A)/(1 + cot^2 A)` = sec² A – 1

Prove that `(cot A - cos A)/(cot A + cos A) = (cos^2 A)/(1 + sin A)^2`

Prove that (sec θ + tan θ) (1 – sin θ) = cos θ

Rehana went to a bank to withdraw ₹ 2000. She asked the cashier to give her ₹ 50 and ₹ 100 notes only. Rehana got 25 notes in all. Find how many notes of ₹ 50 and ₹ 100 did she received.

बुद्धिमती कुत्र व्याघ्र ददर्श?

 भामिनी कया विमुक्ता?

सर्वदा सर्वकार्येषु का बलवती?

व्याघ्रः कस्मात् बिभोति?

 प्रत्युपन्नमतिः बुद्धिमती किम् आक्षिपन्ती उवाच?

बुद्धिमती केन उपेता पितुहं प्रति चलिता?

 व्याघ्रः किं विचार्य पलायित:?

लोके महतो भयात् कः मुच्यते?

जम्बुकः किं वदन् व्याघ्रस्य उपहासं करोति?