Definitions [5]
Let y = f(x). If the first derivative \[\frac{dy}{dx} = f'(x)\] is itself differentiable, then differentiating once again with respect to \[x\] gives the second order derivative.
When x = f(t) and y = g(t), the relation between x and y is said to be in parametric form.
Implicit differentiation means differentiating both sides of an equation with respect to x, while remembering that y depends on x. Therefore, whenever a term containing y is differentiated, the factor \[\frac{dy}{dx}\] appears by the chain rule.
A function may attain a maximum value at a point if its value there is greater than nearby values, and it may attain a minimum value if its value there is smaller than nearby values. These are often called extreme values.
A point in the domain of a function is called a critical point if either the derivative is zero there or the derivative does not exist there. Critical points are checked while locating possible maxima or minima.
Theorems and Laws [3]
If y = 5 cos x – 3 sin x, prove that `(d^2y)/(dx^2) + y = 0`.
Given, y = 5 cos x – 3 sin x
Differentiating both sides with respect to x,
`dy/dx = 5 d/dx cos x - 3 d/dx sin x`
= 5 (−sin x) − 3 cos x
= −5 sin x − 3 cos x
Differentiating both sides again with respect to x,
`(d^2 y)/dx = - 5 d/dx sin x - 3 d/dx cos x`
= −5 cos x − 3 (−sin x)
= 3 sin x − 5 cos x
Hence, `(d^2 y)/dx^2 + y` = 0
(3 sin x − 5 cos x) + (5 cos x − 3 sin x) = 0 ...(On substituting the value of y)
Assume f'(c) = 0 and the second derivative exists at c:
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Local Maxima: f''(c) < 0
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Local Minima: f''(c) > 0
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Test Fails: f''(c) = 0. If this happens, you must go back and use the First Derivative Test to check if it is a maxima, minima, or point of inflection.
Let c be a critical point of a continuous function f:
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Local Maxima: f'(x) changes sign from positive to negative as x increases through c.
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Local Minima: f'(x) changes sign from negative to positive as x increases through c.
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Point of Inflection: f'(x) does not change sign as x passes through c (it is neither a maxima nor a minima).
Key Points
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Second derivative means differentiating the function twice with respect to the same variable.
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It is defined only when the first derivative is differentiable.
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Common notations are \[\frac{d^2y}{dx^2}\], f''(x), y'', \[D^2y\], and \[y_2\].
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Higher order derivatives can be defined similarly.
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Parametric form means both x and y are written in terms of a third variable.
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The third variable is called the parameter.
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The main formula is:
\[\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}\] -
This formula is based on the chain rule.
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Always check that \[\frac{dx}{dt} \neq 0\].
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The final answer may remain in terms of the parameter unless the question asks for conversion.
- If an equation contains both x and y and cannot be solved directly for y, it is called an implicit function.
- Implicit functions are generally written in the form:
f(x, y) = 0 - To differentiate an implicit function, differentiate both sides with respect to x, treating y as a function of x.
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Maxima and minima are extreme values of a function.
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Critical points occur where \(f'(x)=0\) or \(f'(x)\) is not defined.
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If \(f'(x)\) changes from positive to negative, the function has a local maximum.
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If \(f'(x)\) changes from negative to positive, the function has a local minimum.
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If \(f''(c) < 0\), there is a local maximum at \(x=c\).
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If \(f''(c) > 0\), there is a local minimum at \(x=c\).
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For absolute extrema on \([a,b]\), compare values at critical points and endpoints.
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Not every critical point gives a maximum or minimum.
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The second derivative test is quick, but the first derivative test is often more reliable in detailed reasoning.
