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X is a normally distributed variable with mean µ = 30 and standard deviation σ = 4. Find P(30 < X < 35)

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प्रश्न

X is a normally distributed variable with mean µ = 30 and standard deviation σ = 4. Find P(30 < X < 35)

बेरीज
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उत्तर

Given X ~ N(µ, σ2)

µ = 30

σ = 4

P(30 < X < 35) = ?

When x = 30

z = `(35 - 30)/4 = 5/4` = 1.25

P(30 < x < 35) = P(0 < z < 1.25)

= 0.3944

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पाठ 7: Probability Distributions - Miscellaneous problems [पृष्ठ १७२]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
पाठ 7 Probability Distributions
Miscellaneous problems | Q 8. (c) | पृष्ठ १७२

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