मराठी

X 1 + Tan X

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प्रश्न

\[\frac{x}{1 + \tan x}\] 

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उत्तर

\[\text{ Let } u = x; v = 1 + \tan x\]
\[\text{ Then }, u' = 1; v' = \sec^2 x\]
\[\text{ Using the quotient rule }:\]
\[\frac{d}{dx}\left( \frac{u}{v} \right) = \frac{vu' - uv'}{v^2}\]
\[\frac{d}{dx}\left( \frac{x}{1 + \tan x} \right) = \frac{\left( 1 + \tan x \right)1 - x \sec^2 x}{\left( 1 + \tan x \right)^2}\]
\[ = \frac{1 + \tan x - x \sec^2 x}{\left( 1 + \tan x \right)^2}\]
\[\]

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पाठ 30: Derivatives - Exercise 30.5 [पृष्ठ ४४]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 30 Derivatives
Exercise 30.5 | Q 22 | पृष्ठ ४४

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