मराठी

Write two Pythagorean triplets each having one of the numbers as 5.

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प्रश्न

Write two Pythagorean triplets each having one of the numbers as 5.

बेरीज
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उत्तर

Given: We know that for any natural number greater than 1, (2m, m2 – 1, m2 + 1) is a the Pythagorean triplet.

So if one number is m2 + 1 then other two number are m2 – 1 and 2m.

i.e. m2 + 1 = 5  ...(Given)

⇒ m2 = 4

⇒ m = 2

Then m2 – 1

= 22 – 1

= 4 – 1

= 3

And 2m = 2(2) = 4

Hence, Pythagorean triplet is 3, 4 and 5

Similarly another triplet is:

  • We need a2 + b2 = c2
  • Let's try b = 12 and solve for c:
    • 52 + 122 = 25 + 144 = 169
    • c2 = 169
    • c = `sqrt(169)` = 13

Thus, the triplet is (5, 12, 13).

Hence, 3, 4, 5 and 5, 12, 13 are two Pythagorean triplet.

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पाठ 3: Square-Square Root and Cube-Cube Root - Exercise [पृष्ठ ९४]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 8
पाठ 3 Square-Square Root and Cube-Cube Root
Exercise | Q 100. | पृष्ठ ९४

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संबंधित प्रश्‍न

Write a Pythagorean triplet whose one member is 18.


From the pattern, we can say that the sum of the first n positive odd numbers is equal to the square of the n-th positive number. Putting that into formula:
1 + 3 + 5 + 7 + ...  n =  n2, where the left hand side consists of n terms. 


Which of the following triplets are pythagorean? 

 (8, 15, 17)


Which of the following triplet is pythagorean? 

 (18, 80, 82) 


Observe the following pattern \[1 = \frac{1}{2}\left\{ 1 \times \left( 1 + 1 \right) \right\}\]
\[ 1 + 2 = \frac{1}{2}\left\{ 2 \times \left( 2 + 1 \right) \right\}\]
\[ 1 + 2 + 3 = \frac{1}{2}\left\{ 3 \times \left( 3 + 1 \right) \right\}\]
\[1 + 2 + 3 + 4 = \frac{1}{2}\left\{ 4 \times \left( 4 + 1 \right) \right\}\] 

and find the values of  following: 

1 + 2 + 3 + 4 + 5 + ... + 50


Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :  

12 + 22 + 32 + 42 + ... + 102

 

 


Which of the following number  square of even number? 

5476 


Find the square of the following number: 

127 


Find the square of the following number: 

425 


The sum of two perfect squares is a perfect square.


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