Advertisements
Advertisements
प्रश्न
The sides of a right triangle whose hypotenuse is 17 cm are ______ and ______.
Advertisements
उत्तर
The sides of a right triangle whose hypotenuse is 17 cm are 8 and 15.
Explanation:
As, hypotenuse of right angled triangle is 17 cm.
So, 172 = a2 + b2 ...[By Pythagoras theorem]
Where, a and b are other sides of right angled triangle.
= 82 + 152 ...[∵ 172 = 82 + 152]
Hence, a = 8 and b = 15.
As, hypotenuse of right angled triangle is 17 cm.
APPEARS IN
संबंधित प्रश्न
Write a Pythagorean triplet whose one member is 16.
What will be the units digit of the square of the following number?
52
Observe the following pattern
22 − 12 = 2 + 1
32 − 22 = 3 + 2
42 − 32 = 4 + 3
52 − 42 = 5 + 4
and find the value of
1002 − 992
Observe the following pattern
22 − 12 = 2 + 1
32 − 22 = 3 + 2
42 − 32 = 4 + 3
52 − 42 = 5 + 4
and find the value of
1112 − 1092
Which of the following triplet pythagorean?
(16, 63, 65)
Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :
52 + 62 + 72 + 82 + 92 + 102 + 112 + 122
Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication:
54
Find the square of the following number:
575
If one member of a pythagorean triplet is 2m, then the other two members are ______.
The sum of first n odd natural numbers is ______.
