Question

Write the output of the following code:

def Exam2026(given) :
    new=[]
    for ch in given[1:-1]:
        if ch.isupper() :
            new.reverse()
        elif ch not in new:
            new.append(ch)
        elif ch in new:
            new.pop()
    print(new)
Exam2026("Gold-24Medals")

Answer 1

The loop runs on given[1:-1].

• String: G o l d - 2 4 M e d a l s
• Sliced portion: old-24Medal (removes the first 'G' and last 's').

The logic is: If Uppercase → reverse(); If not in list → append(); If already in list → pop().

Character (ch)	Condition	new list
o	Not in new	['o']
I	Not in new	['o', 'l']
d	Not in new	['o', 'l', 'd']
-	Not in new	['o', 'l', 'd', '-']
2	Not in new	['o', 'l', 'd', '-', '2']
4	Not in new	['o', 'l', 'd', '-', '2', '4']
M	Uppercase	['4', '2', '-', 'd', 'l', 'o'] (Reversed)
e	Not in new	['4', '2', '-', 'd', 'l', 'o', 'e']
d	Already in	['4', '2', '-', 'd', 'l', 'o'] (pop() removes 'e')
a	Not in new	['4', '2', '-', 'd', 'l', 'o', 'a']
I	Already in	['4', '2', '-', 'd', 'l', 'o'] (pop() removes 'a')

The final print(new) The command displays the list:

['4', '2', '-', 'd', 'l', 'o']