Advertisements
Advertisements
प्रश्न
Write the following equation in ax + by + c = 0 form: `x/2 + y/4` = 1
Advertisements
उत्तर
`x/2 + y/4` = 1
∴ `(2x + y)/4` = 1
∴ 2x + y = 4
∴ 2x + y – 4 = 0 is the equation in ax + by + c = 0 form.
APPEARS IN
संबंधित प्रश्न
Find the equation of the line passing through the points A(2, 0) and B(3, 4).
Line y = mx + c passes through the points A(2, 1) and B(3, 2). Determine m and c.
The vertices of a triangle are A(3, 4), B(2, 0) and C(1, 6). Find the equations of side BC
The vertices of a triangle are A(3, 4), B(2, 0) and C(1, 6). Find the equations of the line passing through the mid points of sides AB and BC.
Find the equations of the altitudes of the triangle whose vertices are A(2, 5), B(6, – 1) and C(– 4, – 3).
Find the slope, x-intercept, y-intercept of the following line : 2x + 3y – 6 = 0
Find the slope, x-intercept, y-intercept of the following line : x + 2y = 0
Write the following equation in ax + by + c = 0 form: y = 2x – 4
Write the following equation in ax + by + c = 0 form: y = 4
Write the following equation in ax + by + c = 0 form: `x/3 = y/2`
Find the equation of the line whose x-intercept is 3 and which is perpendicular to the line 3x – y + 23 = 0.
Find the X-intercept of the line x + 2y – 1 = 0
Find the equation of the line: having slope 5 and containing point A(– 1, 2).
Find the equation of the line: containing the point (2, 1) and having slope 13.
Find the equation of the line: through the origin which bisects the portion of the line 3x + 2y = 2 intercepted between the co-ordinate axes.
Find the equation of the line passing through the points A(–3, 0) and B(0, 4).
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of the sides
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of the medians.
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of Perpendicular bisectors of sides
