Advertisements
Advertisements
प्रश्न
Find the equation of the line passing through the points A(–3, 0) and B(0, 4).
Advertisements
उत्तर
Since, the required line passes through the points A(–3, 0) and B(0, 4).
Equation of the line in two point form is
`(y - y_1)/(y_2 - y_1) = (x - x_1)/(x_2 - x_1)`
Here, (x1, y1) = (–3, 0) and (x2, y2) = (0, 4)
∴ the equation of the required line is
`(y - 0)/(4 - 0) = (x - (- 3))/(0 - (- 3))`
∴ `y/4 = (x + 3)/3`
∴ 4x + 12 = 3y
∴ 4x – 3y + 12 = 0
APPEARS IN
संबंधित प्रश्न
Find the equation of the line passing through the points A(2, 0) and B(3, 4).
The vertices of a triangle are A(3, 4), B(2, 0) and C(1, 6). Find the equations of side BC
The vertices of a triangle are A(3, 4), B(2, 0) and C(1, 6). Find the equations of the line passing through the mid points of sides AB and BC.
Find the x and y-intercepts of the following line: `x/3 + y/2` = 1
Find the x and y-intercepts of the following line: 2x – 3y + 12 = 0
Find the equations of the altitudes of the triangle whose vertices are A(2, 5), B(6, – 1) and C(– 4, – 3).
Find the slope, x-intercept, y-intercept of the following line : 2x + 3y – 6 = 0
Find the slope, x-intercept, y-intercept of the following line : x + 2y = 0
Write the following equation in ax + by + c = 0 form: y = 4
Find the equation of the line whose x-intercept is 3 and which is perpendicular to the line 3x – y + 23 = 0.
Verify that A(2, 7) is not a point on the line x + 2y + 2 = 0.
Find the X-intercept of the line x + 2y – 1 = 0
Find the equation of the line: containing the point (2, 1) and having slope 13.
Find the equation of the line: having an inclination 60° and making intercept 4 on the Y-axis.
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of the sides
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of the medians.
The vertices of a triangle are A (1, 4), B (2, 3) and C (1, 6). Find equations of Perpendicular bisectors of sides
