Question

Write the sum of intercepts cut off by the plane `vecr.(2hati+hatj-k)-5=0` on the three axes

 

Answer 1

`vecr.(2hati+hatj-k)-5=0`

in Cartesian form

2x + y - z - 5=0

2x + y - z = 5

`(2x)/5+y/5-z/5=1`

`x/"5/2"+y/5+z/(-5)=1`

Intercept cutt of on the axes `(5/2,5,-5)`

`x/a+y/b+z/c=1`

`a=5/2 `        b = 5     c = -5

a + b + c = 5 /2