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प्रश्न
Write Lewis symbols for the following atoms and ions: S and S2–.
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उत्तर १
S and S2–
The number of valence electrons in sulphur is 6.
The Lewis dot symbol of sulphur (S) is 
The dinegative charge infers that there will be two electrons more in addition to the six valence electrons. Hence, the Lewis dot symbol of S2– is 
उत्तर २
`""_16"S"` = 2,8,6 ∴ Lewis symbol = 
, `"S"^(2-) "ions" = ` 
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संबंधित प्रश्न
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| Column I | Column II |
| (i) Hydrogen bond | (a) \[\ce{C}\] |
| (ii) Resonance | (b) \[\ce{LiF}\] |
| (iii) Ionic solid | (c) \[\ce{H2}\] |
| (iv) Covalent solid | (d) \[\ce{HF}\] |
| (e) \[\ce{O3}\] |
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\[\ce{^\bullet_\bullet {\ce{O}} ≡ C - \overset{\bullet\bullet}{\underset{\bullet\bullet}{O^\bullet_\bullet}}}\]
