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प्रश्न
Write the equation of the normal to the curve y = cos x at (0, 1) ?
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उत्तर
\[\text { Given }: \]
\[y = \cos x\]
\[\text { On differentiating both sides w.r.t.x, we get }\]
\[\frac{dy}{dx} = - \sin x\]
\[\text { Now }, \]
\[\text { Slope of the tangent }= \left( \frac{dy}{dx} \right)_\left( 0, 1 \right) =-sin 0=0\]
\[\text { and }\]
\[\text { Equation of the normal }\]
\[ = y - y_1 = \frac{- 1}{m}\left( x - x_1 \right)\]
\[ \Rightarrow y - 1 = \frac{- 1}{0}\left( x - 0 \right)\]
\[ \Rightarrow x = 0\]
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