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प्रश्न
Write the equation for the laboratory preparation of the following salts, using sulphuric acid.
Lead sulphate from lead nitrate.
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उत्तर
\[\ce{Pb(NO3)2 + H2SO4 -> PbSO4 v + 2HNO3}\]
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संबंधित प्रश्न
Which property of sulphuric acid is shown by the reaction of the concentrated sulphuric acid with carbon?
Describe the reaction that show
Dilute sulphuric acid behaves as dibasic acid.
What would you observe in the following case:
Sugar crystals are added to a hard glass test tube containing concentrated sulphuric acid.
In the given equation identify the role played by concentrated sulphuric acid S + 2H2SO4→ 3SO2 + 2H2O
Distinguish between the following pair of compounds using the test given with brackets:
Dilute sulphuric acid and dilute hydrochloric acid (using barium chloride solution)
Give balanced chemical equation to prepare the following salt:
Sodium sulphate using dilute sulphuric acid
Identify the gas evolved and give the chemical test in the following case:
Dilute hydrochloric acid reacts with sodium sulphite.
Give a chemical test to distinguish between dilute sulphuric acid and dilute hydrochloric acid (using lead nitrate solution).
A, B and C are the chemical properties of sulphuric acid:
A. Oxidizing agent
B. Dehydrating agent
C. Non-volatile acid
Match the following equations 1 to 3 to the above chemical properties of sulphuric acid.
1. \[\ce{KNO3 + H2SO4 -> KHSO4 + HNO3}\]
2. \[\ce{C12H22O11 -> 12C + 11H2O}\]
3. \[\ce{S + 2H2SO4 -> 2H2O + 3SO2}\]
What property of Sulphuric acid is exhibited in the following case?
When concentrated Sulphuric acid reacts with Copper to produce Sulphur dioxide gas.
