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Work Done by a Sample of an Ideal Gas in a Process a is Double the Work Done in Another Process B. - Physics

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प्रश्न

Work done by a sample of an ideal gas in a process A is double the work done in another process B. The temperature rises through the same amount in the two processes. If CAand CB be the molar heat capacities for the two processes,

पर्याय

  • CA = CB

  • CA < CB

  • CA > CB

  •  CA and CB cannot be defined.

MCQ
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उत्तर

C> CB
According to the first law of thermodynamics, ΔQ = ΔU + ΔW, where Δ Q  is the heat supplied to the system when ΔW work is done on the system and ΔU  is the change in internal energy produced. Since the temperature rises by the same amount in both processes, change in internal energies are same, i.e. ΔUA = ΔUB.

But as , ΔWA =ΔWB this gives ΔQA = 2ΔQB

Now, molar heat capacity of a gas, C = `(triangleQ) /(ntriangleT)`, where Δ Q/n is the heat  supplied to a mole of gas and ΔT is the change in temperature produced. As ΔQA = 2ΔQB, CA > CB.

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Molecular Nature of Matter
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Specific Heat Capacities of Gases - MCQ [पृष्ठ ७६]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
पाठ 5 Specific Heat Capacities of Gases
MCQ | Q 1 | पृष्ठ ७६

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