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प्रश्न
Without using trigonometric tables, find the value of the expression:
sin (50° + θ) – cos (40° – θ) + tan 1° tan 10° tan 20° tan 70° tan 80° tan 89°
बेरीज
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उत्तर
Given: sin (50° + θ) – cos (40° – θ) + tan 1° tan 10° tan 20° tan 70° tan 80° tan 89°
Step-wise calculation:
1. Use sin x = cos(90° – x):
sin(50° + θ) = cos[90° – (50° + θ)]
= cos(40° – θ)
Hence sin(50° + θ) – cos(40° – θ) = 0.
2. Pair complementary tangents:
tan 1°·tan 89° = tan 1°·cot 1° = 1
tan 10°·tan 80° = tan 10°·cot 10° = 1
tan 20°·tan 70° = tan 20°·cot 20° = 1
Therefore the product tan 1°·tan 10°·tan 20°·tan 70°·tan 80°·tan 89°
= 1·1·1
= 1
⇒ 0 + 1 = 1
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