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प्रश्न
With what least number must 8640 be divided so that the quotient is a perfect cube?
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उत्तर
The prime factors of 8640 are
= 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5
= (2 × 2 × 2) × (2 × 2 × 2) × (3 × 3 × 3) × 5
Clearly, 8640 must be divided by 5. So, that the quotient is a perfect cube.
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संबंधित प्रश्न
\[\sqrt[3]{8 \times . . .} = 8\]
\[\sqrt[3]{} . . . = \sqrt[3]{7} \times \sqrt[3]{8}\]
\[\sqrt[3]{\frac{27}{125}} = \frac{. . .}{5}\]
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