Advertisements
Advertisements
प्रश्न
With what least number must 8640 be divided so that the quotient is a perfect cube?
Advertisements
उत्तर
The prime factors of 8640 are
= 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5
= (2 × 2 × 2) × (2 × 2 × 2) × (3 × 3 × 3) × 5
Clearly, 8640 must be divided by 5. So, that the quotient is a perfect cube.
APPEARS IN
संबंधित प्रश्न
Find the cube root of the following number by the prime factorisation method.
512
Find the cube root of the following number by the prime factorisation method.
91125
Using the method of successive subtraction examine whether or not the following numbers is perfect cube 792 .
\[\sqrt[3]{8 \times . . .} = 8\]
\[\sqrt[3]{\frac{729}{1331}} = \frac{9}{. . .}\]
The volume of a cubical box is 474.552 cubic metres. Find the length of each side of the box.
Three numbers are to one another 2 : 3 : 4. The sum of their cubes is 0.334125. Find the numbers.
Making use of the cube root table, find the cube root
7532 .
Find the cube root of 8000.
The cube root of 0.000004913 is ___________
