Advertisements
Advertisements
प्रश्न
With what least number must 8640 be divided so that the quotient is a perfect cube?
Advertisements
उत्तर
The prime factors of 8640 are
= 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5
= (2 × 2 × 2) × (2 × 2 × 2) × (3 × 3 × 3) × 5
Clearly, 8640 must be divided by 5. So, that the quotient is a perfect cube.
APPEARS IN
संबंधित प्रश्न
Find the cube root of the following number by the prime factorisation method.
64
Using the method of successive subtraction examine whether or not the following numbers is perfect cube 345 .
\[\sqrt[3]{125 \times 27} = 3 \times . . .\]
\[\sqrt[3]{1728} = 4 \times . . .\]
\[\sqrt[3]{480} = \sqrt[3]{3} \times 2 \times \sqrt[3]{. . .}\]
\[\sqrt[3]{. . .} = \sqrt[3]{4} \times \sqrt[3]{5} \times \sqrt[3]{6}\]
Making use of the cube root table, find the cube root
250.
Making use of the cube root table, find the cube root
7342 .
The cube root of 540 × 50 is ___________
By what smallest number should 3600 be multiplied so that the quotient is a perfect cube. Also find the cube root of the quotient.
