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Why does the element carbon from a large number of carbon compounds?

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प्रश्न

Why does the element carbon from a large number of carbon compounds?

दीर्घउत्तर
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उत्तर

The element, carbon, forms a large number of carbon compounds because of its property of self combination (catenation). The ability of one carbon atom to combine with the many other carbon atoms to form long chains produces a large number of carbon compounds. This long chain of carbon atoms supports the other atoms to get attached to it in a number of ways due to which a large number of carbon compounds are obtained.

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पाठ 4: Carbon And Its Compounds - Exercise 1 [पृष्ठ २७२]

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लखमीर सिंह Chemistry Part 2 [English] Class 10
पाठ 4 Carbon And Its Compounds
Exercise 1 | Q 31. (a) | पृष्ठ २७२

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Draw the structures for Ethanoic acid.


Explain why propane cannot exhibit the structural isomerism property.


Give reason why the carbon compounds generally have low melting and boiling points.


Which of the two has a branched chain? 

Isobutane or normal butane


Give the name and structural formula of one member of the following:

Alkyne


What is the unique property of carbon atom? How is this property helpful to us?


Giving the structure, state the number of single bonds, double bonds, and triple bonds (if any) in the following compound:

Benzene


Explain the meaning of saturated hydrocarbons with two examples.


A diamond-toothed saw is usually used for cutting ______.


The pair of elements which exhibits the property of catenation is ______.


The molecular formulae of some organic compounds are given below. Which of these compounds contains an aldehyde group?


Which of the following are correct structural isomers of butane?

  1. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{..}\\
    |\phantom{....}|\phantom{....}|\phantom{....}|\phantom{..}\\
    \ce{H - C - C - C - C - H}\\
    |\phantom{....}|\phantom{....}|\phantom{....}|\phantom{..}\\
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{..}
    \end{array}\]
  2. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - H}\\
    |\phantom{.....}\backslash\phantom{..}|\\
    \phantom{.....}\ce{H}\phantom{.......}\ce{C - H}\\
    \phantom{.........}|\\
    \phantom{.........}\ce{H}
    \end{array}\]
  3. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - H}\\
    |\phantom{....}\phantom{....}|\\
    \ce{H}\phantom{........}\ce{H}\\
    |\\
    \ce{H - C - H}\\
    |\\\ce{H}
    \end{array}\]
  4. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\\
    \ce{H - C - C - H}\\
    |\phantom{....}|\\
    \ce{H - C - C - H}\\
    |\phantom{....}|\\
    \ce{H}\phantom{...}\ce{H}
    \end{array}\]

How many electrons are there in the outermost orbit of carbon?


The number of isomers of pentane is ______.


How many isomers are possible for the compound with the molecular formula C4H8? Draw the electron dot structure of branched-chain isomer. 


How will you prove that C4H8 and C5H10 are homologues?


Recognise the carbon chain type of the following:

\[\begin{array}{cc}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\\ce{H - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\\\ce{H}\phantom{...}\ce{}\phantom{.....}\ce{H}\\
\ce{H - C - H}\\
|\\
\ce{H}
\end{array}\]


Draw two structural isomers of butane.


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