मराठी

Which of the Following Number Are Square of Even Number? 121

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प्रश्न

Which of the following number  square of even number? 

121

 

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उत्तर

The numbers whose last digit is odd can never be the square of even numbers. So, we have to leave out 121

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 1: A Squares - Exercise 3.2 [पृष्ठ २०]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 8
पाठ 1 A Squares
Exercise 3.2 | Q 11.1 | पृष्ठ २०

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संबंधित प्रश्‍न

Write a Pythagorean triplet whose one member is 14.


What will be the units digit of the square of the following number?  

52698 


What will be the units digit of the square of the following number? 

 99880 


Which of the following triplet  pythagorean? 

 (14, 48, 51)


Which of the following triplet pythagorean? 

(16, 63, 65)


Observe the following pattern \[1 = \frac{1}{2}\left\{ 1 \times \left( 1 + 1 \right) \right\}\]
\[ 1 + 2 = \frac{1}{2}\left\{ 2 \times \left( 2 + 1 \right) \right\}\]
\[ 1 + 2 + 3 = \frac{1}{2}\left\{ 3 \times \left( 3 + 1 \right) \right\}\]
\[1 + 2 + 3 + 4 = \frac{1}{2}\left\{ 4 \times \left( 4 + 1 \right) \right\}\]and find the values of following:

31 + 32 + ... + 50


Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :  

12 + 22 + 32 + 4+ ... + 102

 

 


Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :  

52 + 62 + 72 + 82 + 92 + 102 + 112 + 122

 

 


Find the squares of the following numbers using diagonal method: 

 273


Find the area of a square field if its perimeter is 96 m.


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