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प्रश्न
When the current changes from +2A to −2A in 0.05 s, an emf of 8 V is induced in a coil. The co-efficient of self-induction of the coil is
पर्याय
0.2 H
0.4 H
0.8 H
0.1 H
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उत्तर
0.1 H
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संबंधित प्रश्न
What do you mean by self-induction?
How will you define the unit of inductance?
What do you understand by self-inductance of a coil?
Give the physical significance of self-inductance of a coil.
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Show that the mutual inductance between a pair of coils is same (M12 = M21).
Determine the self-inductance of 4000 turn air-core solenoid of length 2m and diameter 0.04 m.
Two air core solenoids have the same length of 80 cm and same cross–sectional area 5 cm2. Find the mutual inductance between them if the number of turns in the first coil is 1200 turns and that in the second coil is 400 turns.
A 200 turn circular coil of radius 2 cm is placed co-axially within a long solenoid of 3 cm radius. If the turn density of the solenoid is 90 turns per cm, then calculate mutual inductance of the coil and the solenoid.
The solenoids S1 and S2 are wound on an iron-core of relative permeability 900. The area of their cross-section and their length are the same and are 4 cm2 and 0.04 m, respectively. If the number of turns in S1 is 200 and that in S2 is 800, calculate the mutual inductance between the coils. The current in solenoid 1 is increased from 2A to 8A in 0.04 second. Calculate the induced emf in solenoid 2.
