Question

When current flowing through one coil changes from 0 Amp to 15 Amp in 0.2 s, an emf of 750 V is induced in an adjacent coil. Calculate the coefficient of mutual inductance of the two coils.

Answer 1

Given: I₁ =  0 

I₂ = 15 A

Δt = 0.2 s

e = 750 V

M = ?

|e| = `M(Delta I)/(Delta t)`

⇒ M = `(|e|)/((Delta I//Delta t))`

= `750/((15 - 0)//0.2)`

= `750/(15//0.2)`

= `750/75`

= 10 H

∴ The coefficient of mutual Inductance is 10 H.