Advertisements
Advertisements
प्रश्न
When 13511, 13903 and 14589 are divided by the greatest number ‘n’, the remainder in each case is ‘m’. The value of (n + m) is
पर्याय
183
182
181
179
Advertisements
उत्तर
183
Explanation:
Let the number are like this:
13511 = a. n + m ....(i)
13903 = b. n + m ....(ii)
and, 14589 = c. n + m ...(iii)
from, (iii - ii), (ii - i), and (iii - i), we get.
14589 – 13903 = 686 = (c – b) .n.
13903 – 13511 = 392 = (b – a) .n.
14589 – 13511 = 1078 = (c – a).n.
Thus, n will be H.C.F of (392, 686, 1078).
∴ n = 98
and, then,
13511 = 137 × 98 + 85
13903 = 141 × 98 + 85
and, 14589 = 148 × 98 + 85
Hence, n = 98 and m = 85
n + m = 98 + 85 = 183
APPEARS IN
संबंधित प्रश्न
Solve the following question and mark the best possible option.
If a, b, c > 0, then find the minimum value of (a + b + c)`(1/(a + b) + 1/(b + c) + 1/(c + a))`.
Solve the following question and mark the best possible option.
Using the digits 1,2 find the number of natural numbers, which are smaller than 2 × 108.
Solve the following question and mark the best possible option.
Find 3x2y2 if x and y are integers such that y2 + 3x2y2 = 30x2 + 517.
Cos3x dx is equal to:
If x = a (t + sin t) and y = a (1 – cos t) then `"dy"/"dx"` is equal to:
`lim_(x->0) |"x - b"|/"x - b"` is equal to:
Find the least number that when divided by 16, 18, and 20 leaves a remainder 4 in each case, but is completely divisible by 7.
The denominator of a fraction is greater than its numerator by 11. If 8 is added to both its numerator and denominator, then it becomes 3/4. The fraction is
2/3 is a rational number whereas √2/√ 3 is:
The sum of the three numbers is 132. If the first number be twice the second and third numbers be one-third of the first. then the second number is
