Question

Find the least number that when divided by 16, 18, and 20 leaves a remainder 4 in each case, but is completely divisible by 7.

पर्याय

• 364

• 2254

• 2884

• 3234

Answer 1

2884

Explanation:

LCM of 16, 18 and 20

= 720

For a condition to Satisfy 720 K + 4. Should be multiple of 7 by putting K = 4

2880 + 4 = 2884 is multiple of 7.