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प्रश्न
What volume will 26.4 g of a gas will occupy at S.T.P. if its vapour density is 22?
संख्यात्मक
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उत्तर
Given:
Mass of gas = 26.4 g
Vapour density = 22
At S.T.P., 1 mole of gas occupies 22.4 L
1. Molar mass = 2 × Vapour density
= 2 × 22
= 44 g mol−1
2. Moles = `26.4/44`
= 0.6 mol
3. Volume = 0.6 × 22.4
= 13.44 L
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