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प्रश्न
What is the value of `(i^(4n + 1) -i^(4n - 1))/2`?
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उत्तर
i, because `(i^(4n + 1) -i^(4n - 1))/2 = (i^(4n)i - i^(4n)i^-i)/2`
= `(i - 1/i)/2`
= `(i^2 - 1)/(2i)`
= `(-2)/(2i)`
= i
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i2 + i3 + ... + i4000 =
