Question

What is the force of repulsion if each sphere is charged double the above amount, and the distance between them is halved?

Answer 1

After doubling the charge, charge on sphere A, q_A = Charge on sphere B, q_B = 2 × 6.5 × 10⁻⁷ C = 1.3 × 10⁻⁶ C

The distance between the spheres is halved.

∴ `"r" = 0.5/2 = 0.25` m

Force of repulsion between the two spheres,

`"F" = ("q"_"A""q"_"B")/(4piin_0r^2)`

= `(9 xx 10^9 xx 1.3 xx 10^-6 xx 1.3 xx 10^-6)/((0.25)^2)`

= 16 × 1.52 × 10⁻²

= 0.243 N

Therefore, the force between the two spheres is 0.243 N.