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Using interpolation estimate the business done in 1985 from the following data Year 1982 1983 1984 1986 Business done(in lakhs) 150 235 365 525 - Business Mathematics and Statistics

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प्रश्न

Using interpolation estimate the business done in 1985 from the following data

Year 1982 1983 1984 1986
Business done
(in lakhs)
150 235 365 525
बेरीज
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उत्तर

Here the intervals are unequal.

By Lagrange’s formula we have,

x0 = 1982

x1 = 1983

x2 = 1984

x3 = 1986

y0 = 150

y1 = 235

y2 = 365

y3 = 525 and x = 1985.

y = `"f"(x) = ((x - x_1)(x - x_2)(x - x_3))/((x_0 - x_1)(x_0 - x_2)(x_0 - x_3)) xx y_0 + ((x - x_0)(x - x_2)(x - x_3))/((x_1 - x_0)(x_1 - x_2)(x_1 - x_3)) xx y_1 + ((x - x_0)(x - x_1)(x - x_3))/((x _2 - x_0)(x_2 - x_1)(x_2 - x_3)) xx y_2 + ((x - x_0)(x - x_1)(x - x_2))/((x_3 - x_0)(x_3 - x_1)(x_3 - x_2)) xx y_3`

y = `((1985 - 1983)(1985 - 1984)(1985 - 1986))/((1982 - 1983)(1982 - 1984)(1982 - 1986)) xx 150 + ((1985 - 1982)(1985 - 1984)(1985 - 1986))/((1983 - 1982)(1983 - 1984)(1983 - 1986)) xx 235  ((198  - 982)(1985 - 1983)(985 - 1986))/((984 - 1982)(1984 - 1983)(1984 - 1986)) xx 365 + ((1985 - 1982)(1985 - 1983)(1985 - 1984))/((1986 - 1982)(1986 - 1983)(1986 - 1984)) xx 525`

= `((2)(1)(-1))/((-1)(-2)(-4)) xx 150 + ((3)(1)(-1))/((1)(-1)(-3)) xx 235 + ((3)(2)(-1))/((2)(1)(-)) xx 365  + ((3)(2)(1))/((4)(3)(2)) xx 525`

= `(-2 xx 150)/(-8) + (-3 xx 235)/3 + (-6 xx 365)/(-4) xx (6 xx 525)/24`

= 37.5 – 235 + 547.5 + 131.25

= 716.125 – 235

= 481.25

∴ Business done in the year 1985 is 481.25 lakhs.

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Interpolation
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पाठ 5: Numerical Methods - Exercise 5.2 [पृष्ठ १२०]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 12 TN Board
पाठ 5 Numerical Methods
Exercise 5.2 | Q 11 | पृष्ठ १२०

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