Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
For the given points (x0, y0) and (x1, y1) the Lagrange’s formula is
पर्याय
`y(x) = (x - x_1)/(x_0 - x_1) y_0 + (x - x_0)/(x_1 - x_0) y_1`
`y(x) = (x_1 - x)/(x_0 - x_1) y_0 + (x - x_0)/(x_1 - x_0) y_1`
`y(x) = (x - x_1)/(x_0 - x_1) y_1 + (x - x_0)/(x_1 - x_0) y_0`
`y(x) = (x_1 - x)/(x_0 - x_1) y_1 + (x - x_0)/(x_1 - x_0) y_0`
Advertisements
उत्तर
`y(x) = (x - x_1)/(x_0 - x_1) y_0 + (x - x_0)/(x_1 - x_0) y_1`
APPEARS IN
संबंधित प्रश्न
Using graphic method, find the value of y when x = 48 from the following data:
| x | 40 | 50 | 60 | 70 |
| y | 6.2 | 7.2 | 9.1 | 12 |
Using Newton’s forward interpolation formula find the cubic polynomial.
| x | 0 | 1 | 2 | 3 |
| f(x) | 1 | 2 | 1 | 10 |
In an examination the number of candidates who secured marks between certain intervals was as follows:
| Marks | 0 - 19 | 20 - 39 | 40 - 59 | 60 - 79 | 80 - 99 |
| No. of candidates |
41 | 62 | 65 | 50 | 17 |
Estimate the number of candidates whose marks are less than 70.
Find the value of f(x) when x = 32 from the following table:
| x | 30 | 5 | 40 | 45 | 50 |
| f(x) | 15.9 | 14.9 | 14.1 | 13.3 | 12.5 |
Using interpolation estimate the output of a factory in 1986 from the following data.
| Year | 1974 | 1978 | 1982 | 1990 |
| Output in 1000 tones |
25 | 60 | 80 | 170 |
Using interpolation estimate the business done in 1985 from the following data
| Year | 1982 | 1983 | 1984 | 1986 |
| Business done (in lakhs) |
150 | 235 | 365 | 525 |
Choose the correct alternative:
If f(x) = x2 + 2x + 2 and the interval of differencing is unity then Δf(x)
A second degree polynomial passes though the point (1, –1) (2, –1) (3, 1) (4, 5). Find the polynomial
Find f(0.5) if f(– 1) = 202, f(0) = 175, f(1) = 82 and f(2) = 55
The area A of circle of diameter ‘d’ is given for the following values
| D | 80 | 85 | 90 | 95 | 100 |
| A | 5026 | 5674 | 6362 | 7088 | 7854 |
Find the approximate values for the areas of circles of diameter 82 and 91 respectively
