मराठी

Using De Broglie’S Hypothesis, Explain with the Help of a Suitable Diagram, Bohr’S Second Postulate of Quantization of Energy Levels in a Hydrogen Atom. - Physics

Advertisements
Advertisements

प्रश्न

Using de Broglie’s hypothesis, explain with the help of a suitable diagram, Bohr’s second postulate of quantization of energy levels in a hydrogen atom.

Advertisements

उत्तर

De Broglie’s Explanation of Bohr’s Second Postulate of Quantisation

• De-Broglie’s hypothesis that electron has a wavelength λ = h/mv gave an explanation for Bohr’s quantised orbits by bringing in the wave particle duality.

• Orbits correspond to circular standing waves in which the circumference of the orbits equal whole number of wavelength.

According to de Broglie’s hypothesis

`lambda = h/p`also for Bohr’s model

It states,

`nlambda = 2pir`

`=> n h/p = 2pir`

`=> rp =n h/(2pi) `            (as rp =L)

`=> L=n h/(2pi)`               Bohr's 2ndPostulate

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2010-2011 (March) All India Set 3

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Plot a graph showing variation of de Broglie wavelength λ versus `1/sqrtV` , where V is accelerating potential for two particles A and B, carrying the same charge but different masses m1, m2 (m1 > m2). Which one of the two represents a particle of smaller mass and why?


A proton and a deuteron are accelerated through the same accelerating potential. Which one of the two has the greater value of de-Broglie wavelength associated with it, and Give reasons to justify your answer.


A proton and an electron have same kinetic. Which one has greater de-Broglie wavelength and why?


Answer the following question.
Obtain the expression for the ratio of the de-Broglie wavelengths associated with the electron orbiting in the second and third excited states of the hydrogen atom.


Light of wavelength 2000 Å falls on a metal surface of work function 4.2 eV.

What will be the change in the energy of the emitted electrons if the intensity of light with same wavelength is doubled?


When the displacement of a particle executing simple harmonic motion is half of its amplitude, the ratio of its kinetic energy to potential energy is:


For an electron accelerated from rest through a potential V, the de Broglie wavelength associated will be:


Find the de-Broglie Wavelength for an electron moving at the speed of 5.0 × 106 m/s. (mass of electron is 9.1 × 10-31)


The work function of a metal is 4.50 eV. Find the frequency of light to be used to eject electrons from the metal surface with a maximum kinetic energy of 6.06 × 10−19 J.


The de-Broglie wavelength (λ) associated with a moving electron having kinetic energy (E) is given by ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×