Advertisements
Advertisements
प्रश्न
Use the given figure to find the value of x in terms of y. Calculate x, if y = 15°.
Advertisements
उत्तर

(2x - y)° = (x + 5)° + (2y + 25)° ....(Exterior angle property)
⇒ 2x° - y° = x° + 5° + 2y° + 25°
⇒ 2x° - x° = 2y° + y° + 30°
⇒ x° = 3y° + 30°
When y = 15, we have
x° = 3 x 15° + 30° = 45° + 30° = 75°.
APPEARS IN
संबंधित प्रश्न
In the given figure, ∠Q: ∠R = 1: 2. Find:
a. ∠Q
b. ∠R
The exterior angles, obtained on producing the side of a triangle both ways, are 100° and 120°. Find all the angles of the triangle.
In a triangle PQR, ∠P + ∠Q = 130° and ∠P + ∠R = 120°. Calculate each angle of the triangle.
Use the given figure to find the value of y in terms of p, q and r.
In a triangle PQR, the internal bisectors of angles Q and R meet at A and the external bisectors of the angles Q and R meet at B. Prove that: ∠QAR + ∠QBR = 180°.
Use the given figure to show that: ∠p + ∠q + ∠r = 360°.
In a triangle ABC. If D is a point on BC such that ∠CAD = ∠B, then prove that: ∠ADC = ∠BAC.
In a triangle ABC, if the bisectors of angles ABC and ACB meet at M then prove that: ∠BMC = 90° + `(1)/(2)` ∠A.
If bisectors of angles A and D of a quadrilateral ABCD meet at 0, then show that ∠B + ∠C = 2 ∠AOD
In a triangle, the sum of two angles is 139° and their difference is 5°; find each angle of the triangle.
