Advertisements
Advertisements
प्रश्न
Two resistors A and B of 4 Ω and 6 Ω respectively are connected in parallel. The combination is connected across a 6 volt battery of negligible resistance. Calculate the power supplied by the battery.
Advertisements
उत्तर
Given,
Resistance, RA = 4 Ω
Resistance, RB = 6 Ω
Voltage, V = 6 V
Ω As resistances are connected in parallel
Equivalent Resistance = `1/"R" = 1/"R"_"A" + 1/"R"_"B"`
`1/"R" = 1/4 + 1/6`
= `10/24`
= `5/12`
R = 2.4 Ω
As power, P = `"V"^2/"R"`
= `(6)^2/2.4`
= 15 W
APPEARS IN
संबंधित प्रश्न
Name the quantity whose unit is (i) kilowatt, and (ii) kilowatt-hour.
How much energy does a 100 W electric bulb transfer in 1 minute?
(a) 100 J
(b) 600 J
(c) 3600 J
(d) 6000 J
An electric bulb is rated ‘100 W, 250 V’. What information does this convey?
Calculate the current through a 60 W lamp rated for 250 V. If the line voltage falls to 200 V, how is the power consumed by the bulb affected?
Write the SI units for:
(a) Electric current
(b) Potential difference
(c) Charge.
Of the three connecting wires in a household circuit: Which two of the three wires are at the same potential? In which of the three wires should the switch be connected?
What would happen and why, to an electric bulb when it is connected across a supply of voltage (i) lower (ii) higher than its proper rating?
With reference to the diagram shown below calculate:

(i) The equivalent resistance between P and Q.
(ii) The reading of ammeter.
(iii) The electrical power between P and Q.
State (i) the S. I. unit, (ii) the household unit, of electrical energy. How are these units related?
The electrical power and current in the circuit relates by ______
