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प्रश्न
Two parallel conductors carrying current of 4.0 A and 10.0 A are placed 2.5 cm apart in vacuum. The force per unit length between them is ______.
पर्याय
6.4 × 10−5 N/m
6.4 × 10−2 N/m
4.6 × 10−4 N/m
3.2 × 10−4 N/m
MCQ
रिकाम्या जागा भरा
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उत्तर
Two parallel conductors carrying current of 4.0 A and 10.0 A are placed 2.5 cm apart in vacuum. The force per unit length between them is 3.2 × 10−4 N/m.
Explanation:
`F = (mu_0 i_1 i_2)/(2 pi r)`
= `(4 pi xx 10^-7 xx 4 xx 10)/(2 pi xx 2.5 xx 10^-2)`
= 3.2 × 10−4 N/m
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