Advertisements
Advertisements
प्रश्न
Two lines l and m intersect at the point O and P is a point on a line n passing through the point O such that P is equidistant from l and m. Prove that n is the bisector of the angle formed by l and m.
Advertisements
उत्तर
Given: Two lines l and m intersect at the point O and P is a point on a line n passing through O such that P is equidistant from l and m i.e., PQ = PR.

To prove: n is the bisector of the angle formed by l and m i.e., n is the bisector of ∠QOR.
Proof: In ΔOQP and ΔORP,
∠PQO = ∠PRO = 90° ...[Since, P in equidistant from l and m, so PQ and PR should be perpendicular to lines l and m respectively]
OP = OP ...[Common side]
PQ = PR ...[Given]
∴ ΔOQP ≅ ΔORP ...[By RHS congruence rule]
⇒ ∠POQ = ∠POR ...[By CPCT]
Hence, n is the bisector of ∠QOR.
Hence proved.
APPEARS IN
संबंधित प्रश्न
ABC is a right angled triangle in which ∠A = 90° and AB = AC. Find ∠B and ∠C.
ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see the given figure). If AD is extended to intersect BC at P, show that
- ΔABD ≅ ΔACD
- ΔABP ≅ ΔACP
- AP bisects ∠A as well as ∠D.
- AP is the perpendicular bisector of BC.

AD is an altitude of an isosceles triangles ABC in which AB = AC. Show that
- AD bisects BC
- AD bisects ∠A
BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.
ABC is an isosceles triangle with AB = AC. Drawn AP ⊥ BC to show that ∠B = ∠C.
In two right triangles one side an acute angle of one are equal to the corresponding side and angle of the other. Prove that the triangles are congruent.
Prove that in a quadrilateral the sum of all the sides is greater than the sum of its diagonals.
In the following figure, BA ⊥ AC, DE ⊥ DF such that BA = DE and BF = EC. Show that ∆ABC ≅ ∆DEF.

Line segment joining the mid-points M and N of parallel sides AB and DC, respectively of a trapezium ABCD is perpendicular to both the sides AB and DC. Prove that AD = BC.
ABCD is quadrilateral such that AB = AD and CB = CD. Prove that AC is the perpendicular bisector of BD.
