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प्रश्न
Two concentric circular loops of radius 1 cm and 20 cm are placed coaxially.
- Find mutual inductance of the arrangement.
- If the current passed through the outer loop is changed at a rate of 5 A/ms, find the emf induced in the inner loop. Assume the magnetic field on the inner loop to be uniform.
संख्यात्मक
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उत्तर
i. M = `(mu_0 pi r^2)/(2 R)`
μ0 = 4π × 10−7
r = 1 cm = 0.01 m
R = 20 cm = 0.2 m
Putting the values,
M = `(4 pi xx 10^-7 xx pi(0.01)^2)/(2 xx 0.2)`
= 0.00986 × 10−7 H
= 9.98 × 10−4 H
ii. |e| = `M (Delta i)/(Delta t)`
Or, |e| = 9.98 × 10−4 H × 5000 A/s
∴ Induced emf (|e|) = 9.98 × 0.5
= 4.99 V
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