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प्रश्न
Three numbers are in the ratio 1 : 2 : 3 and the sum of their cubes is 4500. Find the numbers.
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उत्तर
Suppose the three numbers be x, 2x, 3x
Given: Sum of cube of three numbers is 4500.
x3 + (2x)3 + (3x)3 = 4500
x3 + 8x3 + 27x3 = 4500
36x3 = 4500
x3 = `4500/36`
x3 = 125
x = `root(3)(125)`
x = `root(3)(5 xx 5 xx 5)`
x = `root(3)(5^3)`
x = 5
So, the numbers are, x = 5,
2a = 2 × 5 = 10
3a = 3 × 5 = 15
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| Sr. No. | Number | Power of the root | Root of the power |
| (1) | `(225)^(3/2)` | Cube of square root of 225 | Square root of cube of 225 |
| (2) | `(45)^(4/5)` | ||
| (3) | `(81)^(6/7)` | ||
| (4) | `(100)^(4/10)` | ||
| (5) | `(21)^(3/7)` |
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