Advertisements
Advertisements
प्रश्न
Three numbers are in the ratio 1 : 2 : 3 and the sum of their cubes is 4500. Find the numbers.
Advertisements
उत्तर
Suppose the three numbers be x, 2x, 3x
Given: Sum of cube of three numbers is 4500.
x3 + (2x)3 + (3x)3 = 4500
x3 + 8x3 + 27x3 = 4500
36x3 = 4500
x3 = `4500/36`
x3 = 125
x = `root(3)(125)`
x = `root(3)(5 xx 5 xx 5)`
x = `root(3)(5^3)`
x = 5
So, the numbers are, x = 5,
2a = 2 × 5 = 10
3a = 3 × 5 = 15
APPEARS IN
संबंधित प्रश्न
Find the cubes of the following number by column method 72 .
Find the cube of \[- \frac{13}{8}\] .
Find the cube root of the following rational number \[\frac{- 19683}{24389}\] .
Evaluate of the following
\[\sqrt[3]{\frac{729}{216}} \times \frac{6}{9}\]
Find the cube of: 7
Find the cube of 1.6.
Which of the following are cubes of an even number
216, 729, 3375, 8000, 125, 343, 4096 and 9261.
Ones digit in the cube of 38 is ______.
Cube of an even number is odd.
Square of a number is positive, so the cube of that number will also be positive.
